Question

A bomber diving at an angle of 53 degrees with the VERTICAL, releases the bomb at...

A bomber diving at an angle of 53 degrees with the VERTICAL, releases the bomb at an altitude of 730m. The bomb hits the ground 5s later.

(a) What is the velocity of the bomber

(b) how far does the bomb travel horizontally during it's flight?

(c) what were the horizontal and vertical velocity components just before hitting the ground?

correct answers:

a-202

b-806

c-161 and 171

Please explain.

Thanks in advance!

Science   Physics   
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