Question

A block of material with a density of 868 kg/m3 is floating in a fluid that has a density of 1040 kg/m3. What fraction of the object is above the surface of the fluid?

Answer #1

let the fraction of object above surface of liquid be

Let volume of object be V

For equilibrium of objcet, weight of object = buoyant force

868*V*g = 1040*V*(1-)*g

=0.165

therefore, 16.5% of the objcet is above surface of fluid

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