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1) Using rotational kinematics
500*2 = wot+ 1/2t2
as the object was initially at rest, we have
500*2 = 1/2t2
= 40 rev/sec2 ( 1 rev = 2)
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4) SAME AS ABOVE
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6) DEPENDS ON (5) WHICH YOU DIDN'T PROVIDE
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7) I assume that you want to know minimum tension at the bottom
minimum velocity ar bottom
sqrt (5gr)
mv2 / r = T - mg
m*5gr / r = T- mg
5mg = T - mg
T = 6mg
T = 352.8 N
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