Question

Assuming the hill is (d=23.4 m ) long , determine the work done on the wrestlerby...

Assuming the hill is (d=23.4 m ) long , determine the work done on the wrestlerby frictionas he slides down the hill. the unitfor work is joules. Also, indicate whethe the work done is positive or negative.

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Answer #1

Work done by a constant force = F.d

Here F is force and d is displacement

Work done by friction force = -fd

Friction force is always opposite to displacement so work done by friction is negative.

Work done for given problem = - f(23.4)

W = -23.4f joules

Work done is negative.

If angle of hill is and friction coefficient is , then friction force is

f = mgcos

So work done is = -23.4mgcos

If wrestler is moving with constant velocity then friction force is equal to mgsin

In that case work done by friction force = - 23.4mgsin

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