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Initially at rest, a small copper sphere with a mass of 1.71

Initially at rest, a small copper sphere with a mass of 1.71

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Answer #1

By conserving energy,

Workd done by Electric field = Kinetic energy gained

So, Vq = 0.5*mv^2

So, v = sqrt(2Vq/m) = sqrt(2*6870*5.37*10^-4/(1.71*10^-6)) = 2077.2 m/s

Now after enetering the magnetic field, the magnetic force will provide the necessary centripetal force for the sphere to exhibit circular motion

So, mv^2/r = qvB

where v = speed

B = 4.09 T

r = radius of curvature

So, r = mv/qB

= 1.71*10^-6*2077.2/(5.37*10^-4*4.09)

= 1.61 m <-----------answer

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