Question

An electron is moving in the direction of a uniform electric field. What happens to the...

An electron is moving in the direction of a uniform electric field. What happens to the potential energy of the electron? Is the electron moving to a location of lower or higher potential?

a.potential energy increases, higher potential.

b.potential energy increases, lower potential.

c.potential energy decreases, higher potential.

d. potential energy decreases, lower potential

Homework Answers

Answer #1

B) potential energy increases, lower potential

In this case,the accelaration(and hence force) is opposite to the motion,net work done is negative,and hence by work energy theorem,kinetic energy decreases.since only conservative forces are involved,total mechanical energy is conserved therefore potential energy should increase.

It is going with the electric field so the field lines move from higher to lower potential so the electron is moving to a location of lower potential.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1) An electric field is directed in the +î direction. An electron is fired in the...
1) An electric field is directed in the +î direction. An electron is fired in the +î direction into the field. Its potential energy ________ and its kinetic energy_________. Think about this from a kinematics perspective. NOTE: You must provide an explanation for your answer to receive credit. a.  increases; increases b.  decreases; increases c.  increases; decreases d.  decreases; decreases 2) You find the following statements on a popular physics-student website. If the statement is correct, explain why. If the statement is incorrect, explain...
A uniform electric field of magnitude 364 N/C pointing in the positive x-direction acts on an...
A uniform electric field of magnitude 364 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 3.00 cm. (a) What is the work done by the field on the electron? (b) What is the change in potential energy associated with the electron? (c) What is the velocity of the electron? Magnitude (m/s) ? Direction (+x, -x, -y, +y)?
An electron moving parallel to a uniform electric field increases its speed from 2.5×107 m/s to...
An electron moving parallel to a uniform electric field increases its speed from 2.5×107 m/s to 4.5×107 m/s over a distance of 1.4 cm. What is the electric field strength?  
As an electron moves in an electric field, its speed decreases from 8.00 × 106 m/s...
As an electron moves in an electric field, its speed decreases from 8.00 × 106 m/s to 2.00 × 106 m/s. (a) Does the electron move to a higher potential or a lower potential? Justify your answer. (b) What is the change in the potential during the electron’s travel? Hint: Use conservation of energy.
A point charge q is moving in uniform electric field (E0 in the z-direction) and uniform...
A point charge q is moving in uniform electric field (E0 in the z-direction) and uniform magnetic field (B0 field in the x-direction). (i) What is the force acting on the charge particle? Find equations of motion for the charge particle. (ii) Assume that initially the charge is placed the origin and has initial velocity (E0/2B0) in the y-direction. Determine position and velocity of the charge particle as a function of time. (iii) Find the trajectory of the particle and...
An electron is initially at rest in a uniform electric field having a strength of 1.95...
An electron is initially at rest in a uniform electric field having a strength of 1.95 × 106 V/m. It is then released and accelerated by the presence of the electric field. What is the change in the electron’s kinetic energy, in kiloelectron volts, if it travels over a distance of 0.25 m in this field? Over how many kilometers would it have to be accelerated in the same electric field to increase its kinetic energy by 65 GeV? &...
QUESTION When an electron is released from rest in a constant electric field, how does the...
QUESTION When an electron is released from rest in a constant electric field, how does the electric potential energy associated with the electron, and the kinetic energy of the electron, change with time? (Select all that apply.) options:The electric potential energy becomes more negative.The electric potential energy becomes more positive.The kinetic energy becomes more negative.The kinetic energy stays the same.The electric potential energy stays the same.The kinetic energy becomes more positive. Use the worked example above to help you solve...
Part A An electron is moving east in a uniform electric field of 1.51 N/CN/C directed...
Part A An electron is moving east in a uniform electric field of 1.51 N/CN/C directed to the west. At point A, the velocity of the electron is 4.53×105 m/sm/s pointed toward the east. What is the speed of the electron when it reaches point B, which is a distance of 0.360 mm east of point A? Express your answer in meters per second. Part B A proton is moving in the uniform electric field of part A. At point...
Part A An electron is moving east in a uniform electric field of 1.51 N/CN/C directed...
Part A An electron is moving east in a uniform electric field of 1.51 N/CN/C directed to the west. At point A, the velocity of the electron is 4.53×105 m/sm/s pointed toward the east. What is the speed of the electron when it reaches point B, which is a distance of 0.360 mm east of point A? Express your answer in meters per second. Part B A proton is moving in the uniform electric field of part A. At point...
An electron is traveling through a uniform electric field. The constant electric field is given by...
An electron is traveling through a uniform electric field. The constant electric field is given by . At t = 0, the electron is at (0, 0) and traveling in the positive z direction with a speed of 5 m/s. a) What is its position 5.0 s later? b) What is the magnitude and direction of the particle's velocity at 5.0 s? EDIT: Oops! E = (-3.00 x 10^-11 N/C)i - (2.00 x 10^-11 N/C) j + (1.00 x 10^-11...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT