Question

A wooden beam with mass of 30 kg is placed over two supports. The beam is just resting on top of the supports - it is not connected to the supports. The beam is 5 meters long and 2 meters is cantilevered out over the right-hand support. How far from the right end of the beam could a 50 kg person stand before the beam tips? (Hint: Think about what happens to the left reaction force when the beam just begins to tip)

(3m separating the two supports, and 2m off the right support)

_________

|---3---|--2--|

Answer #1

**let m = 30 kg
M = 50 kg**

**let x is distance of oerson from right end.**

**when the beam about to tip, the left reaction force
beceomes zero.**

**As the beam is in equilibrium net force and net torque
actin on the beam must be zero.**

**Apply, net torque about right support = 0**

**m*g*0.25 - M*g*(2 - x) = 0**

**m*g*0.25 - 2*M*g + M*g*x = 0**

**M*g*x = 2*M*g - 0.25*m*g**

**x = (2*M*g - 0.25*m*g)/(M*g)**

**x = 2 - 0.25*m/M**

**= 2 - 0.25*30/50**

**= 1.85 m
<<<<<<<<<-------------------Answer**

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