Question

1. A 2.05 kg ball is attached to the bottom end of a length of 9 lb (40.1 N) fishing line. The top end of the fishing line is held stationary. The ball is released from rest while the line is taut and horizontal (? = 90.0

Answer 1

1.Max Vert Force from ball = 2.05 x 9.81 = 20.0 N

Draw a diagram and you get a triangle. The angle the string makes at breaking = ?

Horizontal component of that force = 20 cos ?

Max that force can be = 40.1 N

Solve the triangle:

mg / 40.1 = sin ?

? = sin^-1 (20 / 40.1)

? = 29.91 degrees

Draw out the triangle of forces and then it is simple geometry. You must learn to do these yourself or you will not succeed.

2.work enegy theorm

2.25*9.81*h-.65*2.25*9.81=.5*2.25*3.10^2

h=1.13m