A diving board oscillates with simple harmonic motion of
frequency 3.85 Hz.
What is the maximum amplitude with which the end of the board can
vibrate in order that a pebble placed there not lose contact with
the board during the oscillation?
The max acceleration of the end of the board is:
amax = Aw2 = A (2πf)2
The idea is that if this acc exceeds g, then the pebble willlose contact (because the acc of the board will "overcome" the accof g pulling down).
So to find the maximum allowable value of A, we can set thisequal to g:
g = A(2πf)2 or A = g / 4π2f2
or:
A = 9.8 / 4 * π2 *3.852 = 0.0167 meter
Get Answers For Free
Most questions answered within 1 hours.