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A uniform string of length 20.0 m and weight 0.29 N is attached to the ceiling....

A uniform string of length 20.0 m and weight 0.29 N is attached to the ceiling. A weight of 2.00 kN hangs from its lower end. The lower end of the string is suddenly displaced horizontally. How long does it take the resulting wave pulse to travel to the upper end?

Can anyone explain this with steps and explain their steps? Thank you!

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Answer #1

wave velocity in a stretched string is equal to Sq Rt(Tension force of string/linear mass density of string)

Tension force = 2000 N (weight of string is negligible)
Linear Mass density = m/L
Length = 20 m
Mass = 0.29 N/9.8 m/s = 0.0296 kg

Therefore, Linear Mass Density = .0296kg/20 m = 0.00148 kg/m

Tension Force/Linear mass density = 2000 N/0.00148 = 1351351.135 m/s

SqRT(1351351.135) = 1162.47 m/s = wave velocity

t = d/v = 20/1162.47 = 1.72 x 10^-2 seconds

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