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Acceleration from acceleration, time graph: 0.686 m/s2 Acceleration from velocity, time graph: 0.686 m/s2 Let’s see...

Acceleration from acceleration, time graph: 0.686 m/s2

Acceleration from velocity, time graph: 0.686 m/s2

Let’s see what your results would predict for g. Determine this value using the average of your two acceleration values.

1. Predicted maximum acceleration, aavg/sin(θ) = ___________m/s2

Compare this result to the value assumed in the lab, 9.80 m/s2 by finding the percentage error.

2. Percentage error____________ %

**Please show all work, it is for a lab**

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Answer #1

Answer: As given, value of acceleration from acceleration-time graph is 0.686 m/s2 and also, from the velocity-time graph is 0.686 m/s2.

Thus, aavg = (0.686 +0.686)/2 = 0.686 m/s2

1) Predicted maximum acceleration = aavg/sin(θ) = 0.686/1 = 0.686 m/s2. Answer [for maximum acceleration, sin(θ) =1]

2) Percentage Error = (Assumed value - Predicted max. acceleration)*100/ (Assumed value)

Here, Predicted max. acceleration = 0.686 m/s2 and Assumed value = 9.80 m/s2.

=> % Error = (9.80-0.686)*100/9.80

=> % Error = 93%. Answer

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