Question

The inside of a Carnot refrigerator is maintained at a temperature of 277 K, while the temperature in the kitchen is 305 K. Using 3027 J of work, how much heat can this refrigerator remove from its inside compartment? |QC| =

Answer 1

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Temperature inside =Tc =271 K

Temperature in the kitchen =Th=299 K

Coefficient of performance of Carnot refrigerator =Tc / (Th - Tc)

Coefficient of performance =277 /[305 -277 ] =271 /28

Coefficient of performance =heat extracted / work done

Heat extracted = Coefficient of performance * work done

Heat extracted =[ 271 /28 ]*3027 = 29297.035J

This refrigerator remove 29297 J
heat from its inside compartment
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