Question

A 2,500-kg car moving east at 10.0 m/s collides with a 3,000-kg
car moving north. The cars stick together and move as a unit after
the collision, at an angle of 35.0 degrees north of east and at a
speed of 5.55 m/s. Find the speed of the 3,000-kg car before the
collision.

__________ m/s north

Answer #1

the momentum in the east= 2500 kg x 10 m/s = 25000 kg m/s

So now we can split up the collided mass' velocity into its
components parts, allowing a right- angled triangle to be drawn,
where 25000 is the the adjacent side to the angle 35.0, and the
momentum in the north direction is the opposite

therefore we know, from trigonometry that

tan 35 = opposite/ adj = opp/ 25000

0.7 = opp/25000

17505 = opp

therefore the momentum of the mass in the north direction is
17505

since momentum= mass x velocity

17505= 3000 x velocity

17505/ 3000 = 5.83 m/s

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