Question

A piece of purple plastic is charged with 5.59×10^6extra electrons compared to its neutral state. What is its net electric charge (including its sign) in coulombs?

net electric charge:

CC

A glittering glass globe is given a net electric charge of 4.05×10−64.05×10−6 C. Does the globe now have more or fewer electrons than it does in its neutral state?

more

fewer

How many more or fewer?

amount:

electrons

Answer 1

Given that number of extra elctrons in plastic (n)=5.59(1000000)=5590000

Using Q=ne

Where n is number of extra elctrons and e the valueof charge on elctron.

Q=(5590000)(1.6)/10^19

Q=8.94/10^13 coulomb

Since plastic has extra electron so sign of charge is negative.

Answer of part two:-

Net elctric charge on glass=40.5-640.5-6=-606 C

Since net charge on glass is negative so it has more number of elctrons than its neutral state.

To find extra number of electrons we use Q=ne

n=Q/e=606(10^19)/1.6=378.75(10^19).

Note:- To divide by charge on elctron i am directly write the value in such a way that power is always positive.example i write 10^19 .