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P7E1 A 60 kg cabinet, initially at rest, is being pushed across the floor with a...

P7E1 A 60 kg cabinet, initially at rest, is being pushed across the floor with a horizontal force (F) = 20.0 N as shown in the diagram. A kinetic friction force (fk) opposes the motion. After the cabinet has moved a distance of 4.00 m horizontally, the speed of the cabinet is 1.20 m/s. Cabinet

a) Use the Work - Kinetic Energy Theorem to determine the net work done on the cabinet. Wnet = 43.2 J Correct: Your answer is correct.

b) Use the Work - Kinetic Energy Theorem to find the magnitude of the friction force acting on the cabinet. fk = 20.0 N Incorrect: Your answer is incorrect.

c) What was the work done by the friction force (fk)? Wfk =

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Answer #1

a)

Work done by all the forces = change in kinetic energy

b)

Work done by horizontal force

Work done by friction

Friction force   ( negative since it acts opposite to force F)

Magnitude of friction force is

c)

Work done by friction force is

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