Question

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 45.0 m/s , and it leaves the bat traveling to the left at an angle of 35 ∘ above horizontal with a speed of 65.0 m/s . The ball and bat are in contact for 1.65 ms .

A. Find the horizontal component of the average force on the
ball. Take the *x*-direction to be positive to the right
(two sig figs)

B. Find the vertical component of the average force on the ball. (Two sig figs)

Answer #1

a)

Initial horizontal component of the momentum is

Pix = mv

Pix = 0.145 kg x 45 m/s = 6.525 kg.m/s

final horizontal component of the momentum is

Pfx = mvf

Pfx = -0.145 kg x 65 m/s x cos(35) = -7.72 kg.m/s

horizontal component of average force on ball is

Fx = Px / t

Fx = Pfx - Pix / t

Fx = ( -7.72 kg.m/s - 6.525 kg.m/s) / (1.65 x 10^-3 s)

Fx = -8.63 x 10^3 N

direction of force is towards left

b)

Initial vertical component of the momentum is

Pix = mv

Pix = 0

final verticle component of the momentum is

Pfy = mvf

Pfy = 0.145 kg x 65 m/s x sin(35) = 5.41 kg.m/s

vertical component of average force on ball is

Fy = Py / t

Fy = Pfy - Piy / t

Fy = ( 5.41 kg.m/s - 0 kg.m/s) / (1.65 x 10^-3 s)

Fy = 3.28 x 10^3 N

direction is upward

direction of force is towards left

A bat strikes a 0.145-kg baseball. Just before impact, the ball is
traveling horizontally to the right at 49.0 m/s ; when it leaves
the bat, the ball is traveling to the left at an angle of 31.0 ∘
above horizontal with a speed of 54.0 m/s . The ball and bat are in
contact for 1.61 ms . Find the horizontal and vertical componenets
of the average force on the ball

A bat strikes a 0.145-kg baseball. Just before impact, the ball
is traveling horizontally to the right at 55.0 m/s , and it leaves
the bat traveling to the left at an angle of 35 ? above horizontal
with a speed of 60.0 m/s . The ball and bat are in contact for 1.85
ms .
A. Find the horizontal component of the average force on the
ball. Take the x-direction to be positive to the right
Express your answer...

A 0.145-kg baseball pitched horizontally at 31.8 m/s strikes a
bat and is popped straight up to a height of 56.2 m. If the contact
time is 1.80 ms, calculate the magnitude of the average force on
the ball during the contact. Calculate the direction of the average
force on the ball during the contact.

A 0.145-kg baseball pitched horizontally at 37.9 m/s strikes a
bat and is popped straight up to a height of 54.0 m .
If the contact time is 1.90 ms , calculate the magnitude of the
average force on the ball during the contact.
Calculate the direction of the average force on the ball during
the contact.

A 0.165-kg baseball pitched horizontally at 38.0 m/s strikes a
bat and is popped straight up to a height of 33.0 m . If the
contact time between bat and ball is 1.0 ms , calculate the
magnitude of the average force between the ball and bat during
contact. Find the direction of the avg force on the ball ∘ from the
initial direction of motion of the ball.

A 0.135-kg baseball pitched horizontally at 30.5 m/s strikes a
bat and is popped straight up to a height of 36.5 m.
Part A:
If the contact time between bat and ball is 3.0 ms , calculate
the magnitude of the average force between the ball and bat during
contact.
Favg = ____ N
Part B:
Find the direction of the average force on the ball.
Theta = __ degrees

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contact time between bat and ball is 2.5 ms , calculate the
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A baseball of mass 0.145 kg is thrown at a speed of 40.0 m/s.
The batter strikes the ball with a force of 29,000 N; the bat and
ball are in contact for 0.500 ms. The force is exactly opposite to
the original direction of the ball.
1)
Determine the final speed of the ball.

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A baseball approaches home plate at a speed of 47.0 m/s, moving
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