Consider a slingshot with a mass 1 kg that is spinning at the end of a 20 cm long rope with a constant speed of 10 m/s. Find the work done by the rope during one half of a revolution. Please explain, answer is in Joules
centripetal force
centripetal force acts on an object moving in circle at constant speed, the force acts inward as the velocity is always directed tangent to the circle.
Here the forces acting on the mass are centripetal force and gravitational force. The horizontal circular motion of mass is due to the centripetal force .
So, work done by centripetal force = F.S
=
=
total displacement in completing half circle is 40 cm and cos 90 = 0
= 0
work done by centripetal force i.e, by the rope during one half of the revolution is 0 joules.
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