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a box is initially at rest at the bottom of frictionless ramp that is inclined at...



a box is initially at rest at the bottom of frictionless ramp that is inclined at an angle theta = 30.0 above the horizontal. you pushed the box horizontally with a force that has amagnitude 150 N. and the box accelerates up the ramp at a rate of 0.750m/s2. a. what is the mass of the box. b. how long will it take to push the bos 1.20 m up the inclined plane.

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Answer #1

Given = 30deg and horizontal force = 150 N  

acceleration = 0.75m/s2

on an inclined plane weight of box mg acts vertically downwards which can be split into two components

mgsin acting downwards along the inclined plane and mgcos scting downwards perpendicular to the inclined plane

Net Force = mass * acceleration

Fcos30 - mgsin30 = m*a

150cos30 = m(gsin30 +a)

m = 150cos30 /(gsin30 +a) = 22.97 kg

ANSWER : Mass = 22.97 kg

----------------

s=ut +1/2at2

Given s =1.2 m , a =0.75m/s2

1.2 = 0 + 0.5 *0.75 *t2

t = 1.789s

ANSWER : Time = 1.8 sec

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