a box is initially at rest at the bottom of frictionless ramp that
is inclined at an angle theta = 30.0 above the horizontal. you
pushed the box horizontally with a force that has amagnitude 150 N.
and the box accelerates up the ramp at a rate of 0.750m/s2. a. what
is the mass of the box. b. how long will it take to push the bos
1.20 m up the inclined plane.
Given = 30deg and horizontal force = 150 N
acceleration = 0.75m/s2
on an inclined plane weight of box mg acts vertically downwards which can be split into two components
mgsin acting downwards along the inclined plane and mgcos scting downwards perpendicular to the inclined plane
Net Force = mass * acceleration
Fcos30 - mgsin30 = m*a
150cos30 = m(gsin30 +a)
m = 150cos30 /(gsin30 +a) = 22.97 kg
ANSWER : Mass = 22.97 kg
----------------
s=ut +1/2at2
Given s =1.2 m , a =0.75m/s2
1.2 = 0 + 0.5 *0.75 *t2
t = 1.789s
ANSWER : Time = 1.8 sec
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