Question

1. A 500-kg elevator is pulled upward with a constant force of 4900 N for a...

1. A 500-kg elevator is pulled upward with a constant force of 4900 N for a distance of 50.0 m at constant speed.

(a) What is the work done by the 4900-N force?

(b) What is the work done by gravity?

(c) Explain the energy transformations taking place as the elevator is pulled upward.

Please explin so that i can understand each step.....Thank you!!!

Homework Answers

Answer #1

a) Work done by the force

Here is the work done is positive as the force and displacement are in the same direction.

b)Work done by gravity is

Here work done is negative as the force and displacement are in opposite directions.

c) Since the elevator is moving with constant speed, kinetic energy of elevator is not increasing. That is net workdone by all forces on the elevator are zero.

The energy delivered to the elevator by the motor of the elevator is being used to do work against gravitation at the same rate. Hence no change in kinetic energy of the elevator.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A(n) 603 kg elevator starts from rest. It moves upward for 3.88 s with a constant...
A(n) 603 kg elevator starts from rest. It moves upward for 3.88 s with a constant acceleration until it reaches its cruising speed of 1.78 m/s. The acceleration of gravity is 9.8 m/s 2 . Find the average power delivered by the elevator motor during this period. Answer in units of kW.
A box with mass 1.74 kg is being pulled across a rough surface at a constant...
A box with mass 1.74 kg is being pulled across a rough surface at a constant speed with a coefficient of kinetic friction µk = 0.366. The pulling force has a magnitude of 11.2 N and is directed at an angle 32.8 degrees above horizontal. If the box is dragged a distance of 10.3 m, what is the total energy lost to friction? (Hint: be sure to account for the upward component of the pulling force, and note that the...
An elevator car including the passengers has a mass of 1100 kg and travels downwards at...
An elevator car including the passengers has a mass of 1100 kg and travels downwards at constant speed of 4.000 m/s for 32.00 m. The force of friction averaging 80.00 N acts on the elevator. The work done by the force of gravity; the work done by the force of friction; and the work done by the cable supporting the elevator during the 32.00 m excursion were (in that order, in kJ): Answer: 345.0; -2.560; -342.4
Suppose a 1300-kg elevator car is lifted a distance 39 m by its cable at a...
Suppose a 1300-kg elevator car is lifted a distance 39 m by its cable at a constant speed, assuming the frictional force on the elevator has a constant value of 95 N. Part (a). Calculate the work done on the elevator by its cable, in joules. Part (b). Calculate the work done by the gravitational force on the elevator, in joules, during this process. Part (c). Calculate the total work done on the elevator, in joules.
(a) A constant 20 N force pushes a small ball in the direction of the force...
(a) A constant 20 N force pushes a small ball in the direction of the force over a distance of 5.0 m. What is the work done by the force? (b) A toy cart is pulled a distance of 6.0 m in a straight line across the floor. The force pulling the cart has a magnitude of 20 N and is directed at 37° above the horizontal. What is the work done by this force? (c) A sled plus passenger...
In the figure, a 0.23 kg block of cheese lies on the floor of a 970...
In the figure, a 0.23 kg block of cheese lies on the floor of a 970 kg elevator cab that is being pulled upward by a cable through distance d1 = 2.1 m and then through distance d2 = 11.5 m. (a) Through d1, if the normal force on the block from the floor has constant magnitude FN = 3.60 N, how much work is done on the cab by the force from the cable? (b) Through d2, if the...
A mass of 0.500 kg stretches a spring 20.0 cm. Find the force constant of the...
A mass of 0.500 kg stretches a spring 20.0 cm. Find the force constant of the spring. If the mass is pulled down an additional distance of 5.00 cm and then released, find the initial restoring force, the period, and the total energy of the resulting simple harmonic motion. 2- Elevator problem with scale (no mass of elevator given). Find what the scale reads if (a) it goes up at 2m/s, (b) up at 8m/s^2 (c) down at 5m/s^2. PLEASE...
Question 1: A 2-kg wood block is pulled by a string across a rough horizontal floor....
Question 1: A 2-kg wood block is pulled by a string across a rough horizontal floor. The string exerts a tension force of 30 N on the block at an angle of 20º above the horizontal. The block moves at constant speed. If the block is pulled for a distance of 3.0 m, how much work is done by the tension force? Question 2: Part A: A spring-loaded toy gun is used to launch a 12.0-g plastic ball. The spring...
A box with mass m=5 (kg) is being pulled with force F=25 (N) horizontally and moves...
A box with mass m=5 (kg) is being pulled with force F=25 (N) horizontally and moves with constant speed. (g = 10 m/s2) a) How much is the coefficient of kinetic friction? b) How much is the Normal force excreted from surface to the box? c) If the box moves 10 (m) in 20 seconds, calculate the work done by force F and by friction. What is the power of Force F?
A 643-kg elevator starts from rest and moves upward for 3.80 s with constant acceleration until...
A 643-kg elevator starts from rest and moves upward for 3.80 s with constant acceleration until it reaches its cruising speed, 1.69 m/s. (a) What is the average power of the elevator motor during this period? . hp (b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with constant speed.) hp
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT