A civil engineer is to design a road curved at a 102 m radius to carry racing cars traveling at 19 m/s.
The acceleration of gravity is 9.8 m/s2 .
At what angle θ should it be banked for maximum control of the racing car?
Answer in units of ◦.
Car is 1.3 Mg
μ = 0.14
Given r =102m
Maximum speed ,v= 19m/s
mass of car =1.3Mg = 1300kg and
Fc =centripetal force =mv2/r
Take x axis parallel to inclined plane
Consider all forces in y direction
N - FcSin - mgcos =0
N = FcSin +mgcos
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Fr is the frictional force = = (FcSin +mgcos)
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Consider all forces in x direction
FcCos -mgsin -Fr =0
FcCos -mgsin -(FcSin +mgcos) =0
Fc(Cos -sin) -mg(Sin+Cos) =0
Divide by Cos
Fc(1 -tan) -mg(tan+) =0
Fc =mv2/r = 1300*192/102 = 4600.98 N
mg =1300*9.81 = 12753 N
4600.98(1 -0.14*tan) -12753(tan+0.14) =0
0.361(1 -0.14*tan) = (tan+0.14)
0.361-0.051tan = (tan+0.14)
0.95tan = 0.221
tan = 0.233
ANSWER:
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