what potential difference is required to send 3.50amps through a 29 ohm resistor?
First of all we specify the given data
The current (I) is = 3.50 amperes
Resistance (R) = 29 Ohm
To Find :- Potential Difference
Solution : Using Ohm's law, Thte potential difference between two points of a circuit is directly proportional to the electric current flowing in the circuit so
V = IR
that is Voltage(Potential Difference) = Current multiplied resistance
replacing the given value in the above equation : -
V = 3.50 x 29
V = 101.50 Volts.
do not forget to specify the units of voltage in answer.
Thanks......
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