Question

The hammer throw is a track-and-field event in which a 7.30-kg ball (the hammer) is whirled around in a circle several times and released. It then moves upward on the familiar curved path of projectile motion and eventually returns to the ground some distance away. The world record for the horizontal distance is 86.75 m, achieved in 1986 by Yuriy Sedykh. Ignore air resistance and the fact that the ball was released above the ground rather than at ground level. Furthermore, assume that the ball is whirled around a circle that has a radius of 2.68 m and that its velocity at the instant of release is directed 38.2 ° above the horizontal. Find the magnitude of the centripetal force acting on the ball just prior to the moment of release.

Answer 1

Given is:-

mass of the ball = 7.30kg

World record of horizontal distance R = 86.75m

radius of the circle r=2.68m

Angle above the horizontal  

Now,

The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from.

The Horizontal range is give by

by plugging all the values we get

which gives

This is the velocity just before the release

Now,

the centripetal force is given by

by plugging all the values we get

which gives

Hence the magnitude of the centripetal force is 2749.3N