QUESTION 1
Calculate the heat energy required to raise the temperature of a cup of water (300 grams) from 25°C to 100°C. Express your answer in Joules. (Be careful with powers of 10)
A |
9.43 x 10e4 J |
|
B |
22,500 J |
|
C |
2.25 x 10e4 J |
|
D |
94,275 x 10e4 J |
|
E |
80 J |
|
F |
335 J |
QUESTION 2
Calculate the heat energy required to raise the temperature of 5 gallons of water from 50 F to 130 F. Express your answer in Btu.
A |
3,320 J |
|
B |
400 x 10e3 Btu |
|
C |
3.32 x 10e3 Btu |
|
D |
20,870 Btu |
|
E |
400 Btu |
|
F |
1676 Btu |
1 points
QUESTION 3
You are measuring the heat capacity of an unknown substance. You add 700 Joules of heat energy to a 100 gram sample of this substance and the temperature increases from 20.5°C to 24°C. Calculate the heat capacity of this substance according to these measurements.
A |
700 J/g °C |
|
B |
0.5 J/g °C |
|
C |
100 J/g °C |
|
D |
7.0 J/g °C |
|
E |
70,000 J/g °C |
|
F |
2.0 J/g °C |
1)
heat energy required = m * S * delta T
heat energy required = 300 * 4.186 * (100 - 25)
heat energy required = 9.43 *10^4 J
the heat energy needed is A) 9.43 *10^4 J
2)
change in temperature , delta T = (130 - 50)
delta T = 80 F
delta T = 80/1.8 = 44.4 degree C
mass of water = 5 gallons = 18.92 kg
heat energy needed = 18.92 * 4186 * 44.4
heat energy needed = 3519960 J = 3320 Btu
the correct option is C) 3.32 *10^3 Btu
3)
Heat capacity = heat energy/(change in temperature * mass)
Heat capacity = 700/((24 - 20.5) * 100)
Heat capacity = 2 J/(gm.degree C)
the correct option is F)
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