A mass of 6 kg is hanging vertically from a rope. Someone pushes up vertically on the mass with a force of 8 Newtons. If the mass is in equilibrium, what is the tension in the rope in Newtons?
Given is:-
mass of the rope = 6kg
Applied vertical force F=8 N
Now,
the free body diagram will be as shown below
According to the Newton's second law, at equilibrium
therefore
or
by plugging all the values we get
which gives us
hence in equilibrium the tension in the rope is 50.8 N
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