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Romeo (160 lb) and Juliet (130 lb) are standing next to each other. They are 1...

Romeo (160 lb) and Juliet (130 lb) are standing next to each other. They are 1 cm apart. If we treat this distance between their hands as the distance between their center of mass which is not true how much is the gravitational acceleration of Romeo towards Juliet. How much is the gravitational acceleration of Juliet towards Romeo?

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Answer #1

Given mass of Romeo = 160lb = 72.574 kg

mass of Juliet = 130lb = 58.967 kg

distance r = 1cm = 0.01 m

Gravitational Force ,F = Gm1m2/r2 , G =6.67 *10-11

Force will be same but acceleration will be different due to different mass

F = (6.67*10-11* 72.574 * 58.967)/0.012

F = 0.00285 N

F=mass*acceleration

a=F/m

Acceleration of Romeo towards Juliet

aR=F/mR

ANSWER : aR = 0.00285/72.574 =3.9*10-5 m/s

Acceleration of Juliet towards Romeo

aJ=F/mJ

ANSWER : aJ = 0.00285/58.967 =4.8*10-5 m/s

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