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An object with a mass of 4.15 kg undergoes an acceleration of -3.1 m/s2 for a...

An object with a mass of 4.15 kg undergoes an acceleration of -3.1 m/s2 for a period of 8.0 s. It then undergoes an acceleration of 5.2 m/s2 for a period of 11.0 s If the initial velocity of the object is 2.36 m/s and it first experiences the acceleration when it is at the origin, plot by hand on graph paper (to scale) the force, velocity, and position as functions of time. Explain why your graphs look the way they do. Include all relevant equations.

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Answer #1

graph shown is just for an idea and not for measurement. I have located all important points for tracing it.

Here force is constant hence parallel to time axis as doesnt vary with time.

Velocity graph is stright line as its slope that is acceleration is constant.

Displacement graph is parabolic as its slope varies with time which is velocity. Value of its slope decides whether curve is concave upward or concave downward.

Eq used is

F=ma

V = u +at

S= S. +ut+ 1/2at^2

Here S. Is initial position if any

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