Question

A soccer ball is kicked from the top of one building with a height of H1 = 29.2 m to another building with a height of H2 = 10.4 m. (It is not a very smart idea to play soccer on the roof of tall buildings.) The ball is kicked with a speed of v0 = 14.7 m/s at an angle of θ = 73.5° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. What is the speed of the soccer ball, when it lands on the roof of the second bulding? The soccer ball is kicked without a spin. Neglect air resistance.

Answer #1

**PROJECTILE**

**along vertical
______________**

**initial velocity v0y = vo*sintheta =
14.7*sin73.5**

**acceleration ay = -g = -9.8 m/s^2**

**initial position y0 = H1 = 29.2 m**

**final position y = H2 = 10.4 m**

**from equation of motion**

**vy^2 - voy^2 = 2*ay*(y-yo)**

**vy^2 - (14.7*sin73.5)^2 = -2*9.8*(10.4-29.2)**

**vy = -23.8 m/s**

**along horizontal
________________**

**initial velocity v0x = vo*costheta =
14.7*cos73.5**

**acceleration ax = 0**

**vx = vox+ a*t**

**vx = 14.7*cos73.5 = 4.18 m/s**

**speed v = sqrt(vx^2 + vy^2) =
sqrt(4.18^2+(-23.8)^2)**

**v = sqrt(17.5+566.44)**

**v=sqrt(583.94)**

**speed v = 24.16 m/s
<<<--------------ANSWER**

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