What is the shape of a projectile's trajectory near the surface of the earth, ignoring air resistance?
Near the surface of earth, the equation of projectile motion. Is given as
y = x tan (theta) - 0.5 g x^2 /( u^2 cos2 (theta))
Where
y = vertical position
x = horizontal position
Theta = angle of projection above horizontal
g = acceleration due gravity ( = 9. 8 m/s^2)
u = velocity of projection
Now the above equation can be considered as the equation of parabola,
Hence the trajectory of projectile near earth's surface is parabolic in nature.
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