Question

a locomotive of mass 400,000 kg (about 440 tons) starts from rest and reaches a speed...

a locomotive of mass 400,000 kg (about 440 tons) starts from rest and reaches a speed of 20 m/s in 16 seconds. what was the locomotive's acceleration in units of m/sec^2? what forces ( in newtons and pounds) was needed to produce this acceleration? how far did the locomotive travel in those seconds?

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Answer #1

Mass of locomotive = m = 400000 kg

Initial speed of locomotive = V1 = 0 m/s

Final speed of locomotive = V2 = 20 m/s

Time period = t = 16 sec

Acceleration of locomotive = a

Distance travelled by locomotive = d

Force acting on locomotive = F

V2 = V1 + at

20 = 0 + a(16)

a = 1.25 m/s2

d = V1t + at2/2

d = 0x16 + (1.25)(162)/2

d = 160 m

F = ma

F = 400000x1.25

F = 500000 N

F = 500000 x 2.204/9.8

F = 112448.98 lbf

Locomotives acceleration = 1.25 m/s2

Force on locomotive = 500000 N = 112448.98 lbf

Distance travelled by the locomotive = 160 m

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