Question

Two 14-cm-diameter electrodes 0.56 cm apart form a parallel-plate capacitor. The electrodes are attached by metal...

Two 14-cm-diameter electrodes 0.56 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 16 V battery.

A,B,C What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes while the capacitor is attached to the battery? Express your answer to two significant figures and include the appropriate units.

D,E,F What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after insulating handles are used to pull the electrodes away from each other until they are 1.1 cm apart? The electrodes remain connected to the battery during this process. Express your answer to two significant figures and include the appropriate units.

G,H,I What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after the original electrodes (not the modified electrodes of parts D-F) are expanded until they are 28 cm in diameter while remaining connected to the battery?

Express your answer to two significant figures and include the appropriate units.

Homework Answers

Answer #1

A. charge Q = CV

here C = eoA/d = 8.85 e -12 * 3.14 * 0.07* 0.07/0.0056

C = 24.32 pF

so

Charge Q = 24.32e -12 * 16 = 3.89 e-10 C

------------------------
B. Electrioc field E = V/d = 16/0.0056 = 2.85 e 3 N/C
---------------------------------

C. Potential difference V = 16 Volts

------------------------------------------

when d = 1.1 cm

D. charge Q = CV

here C = eoA/d = 8.85 e -12 * 3.14 * 0.07* 0.07/0.011

C = 12.37 pF

so

Charge Q = 12.37e -12 * 16 = 1.97 e-10 C

------------------------
E. Electrioc field E = V/d = 16/0.011= 1.32 e 5 N/C
---------------------------------

F. Potential difference V/d = constant

so

V2 = 16 * 0.0056/0.011

V2 = 8.14 Volts

------------------------------------

when D = 28cm r = D/2 = 14.cm or 0.14 m

so

G. charge Q = CV

Here C = eoA/d = 8.85 e -12 * 3.14 * 0.14* 0.14/0.011

C = 49.5 1 pF

so

Charge Q = 49.51 e -12 * 16 = 7.91 e-10 C

------------------------
H. Electrioc field E = V/d = 16/0.011= 1.32 e 5 N/C

---------------------------------

I. Potential difference V/d = constant

so

V2 = 16 Volts

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Two 10.0-cm-diameter electrodes 0.59 cm apart form a parallel-plate capacitor. The electrodes are attached by metal...
Two 10.0-cm-diameter electrodes 0.59 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14 Vbattery. Part A What is the charge on each electrode while the capacitor is attached to the battery? Enter your answers numerically separated by a comma. q1, q2 =   C   Part B What is the electric field strength inside the capacitor while the capacitor is attached to the battery? Express your answer with the appropriate units. E...
Two 13-cm-diameter electrodes 0.46 cm apart form a parallel-plate capacitor. The electrodes are attached by metal...
Two 13-cm-diameter electrodes 0.46 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 13 V battery. DEF What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after insulating handles are used to pull the electrodes away from each other until they are 0.92 cm apart? The electrodes remain connected to the battery during this process. What is the Q=,...
Two 15-cm-diameter electrodes 0.42 cm apart form a parallel-plate capacitor. The electrodes are attached by metal...
Two 15-cm-diameter electrodes 0.42 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14 V battery. After a long time, the capacitor is disconnected from the battery but is not discharged. A) What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after insulating handles are used to pull the electrodes away from each other until they are 0.84 cm...
Two 15-cm-diameter electrodes 0.42 cm apart form a parallel-plate capacitor. The electrodes are attached by metal...
Two 15-cm-diameter electrodes 0.42 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 15 V battery. After a long time, the capacitor is disconnected from the battery but is not discharged. Part D/E/F What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes after insulating handles are used to pull the electrodes away from each other until they are 0.84...
Two 10.0-cm-diameter electrodes 0.59 cm apart form a parallel-plate capacitor. The electrodes are attached by metal...
Two 10.0-cm-diameter electrodes 0.59 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14 Vbattery. What is the charge on each electrode after insulating handles are used to pull the electrodes away from each other until they are 1.1 cm apart? The electrodes remain connected to the battery during this process. q1, q2= ____ C Note: Answer is not 8.9*10^{-10},-8.9*10^{-10} C
A parallel-plate capacitor is formed from two 2.4 cm -diameter electrodes spaced 1.4 mm apart. The...
A parallel-plate capacitor is formed from two 2.4 cm -diameter electrodes spaced 1.4 mm apart. The electric field strength inside the capacitor is 6.0×10^6 N/C. What is the charge (in nC) on each electrode?
A parallel-plate capacitor is formed from two 9.0 cm ×9.0 cm electrodes spaced 2.2 mm apart....
A parallel-plate capacitor is formed from two 9.0 cm ×9.0 cm electrodes spaced 2.2 mm apart. The electric field strength inside the capacitor is 1.0×10^6N/C 1. What is the charge (in nC) on the positive electrode? 2. What is the charge (in nC) on the negative electrode
A parallel-plate capacitor is formed from two 3.0 cmcm ××3.0 cmcm electrodes spaced 2.0 mmmm apart....
A parallel-plate capacitor is formed from two 3.0 cmcm ××3.0 cmcm electrodes spaced 2.0 mmmm apart. The electric field strength inside the capacitor is 1.0×106N/C1.0×106N/C. What is the charge (in nCnC) on the positive electrode? Express your answer in nanocoulombs. Part B What is the charge (in nCnC) on the negative electrode? Express your answer in nanocoulombs.
Two 2.3-cm-diameter electrodes with a 0.20-mm-thick sheet of Teflon between them are attached to a 9.0...
Two 2.3-cm-diameter electrodes with a 0.20-mm-thick sheet of Teflon between them are attached to a 9.0 V battery. Without disconnecting the battery, the Teflon is removed. A)What is the charge before the Teflon is removed? Express your answer using two significant figures. B)What is the potential difference before the Teflon is removed? C) What is the electric field before the Teflon is removed? D)What is the charge after the Teflon is removed? E)What is the potential difference after the Teflon...
A parallel-plate capacitor has 4.7 cm × 4.7 cm electrodes with surface charge densities ±1.0×10−6C/m2. A...
A parallel-plate capacitor has 4.7 cm × 4.7 cm electrodes with surface charge densities ±1.0×10−6C/m2. A proton traveling parallel to the electrodes at 1.6×106 m/s enters the center of the gap between them. By what distance has the proton been deflected sideways when it reaches the far edge of the capacitor? Assume the field is uniform inside the capacitor and zero outside the capacitor. Express your answer to two significant figures and include the appropriate units.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT