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A man weighing 750 N and a woman weighing 460 N have the same momentum. What...

A man weighing 750 N and a woman weighing 460 N have the same momentum. What is the ratio of the man's kinetic energy Km to that of the woman Kw?

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Answer #1

let the mass of man and woman is given as Mm and Mw

Wm = weight of man = Mm g = 750

Ww = weight of woman = Mw g = 460

Ratio of masses is given as

Mm/Mw = 750/460 = 1.63

Given that :

Momentum of man = Momentum of woman

Mm vm = Mw vw

(Mm /Mw) = vw/vm

vw/vm = 1.63

kinetic energy of man is given as

KEm = (0.5) Mm vm2   

and

kinetic energy of woman is given as

KEw = (0.5) Mw vw2   

Ratio of kinetic energy of man and woman is given as

KEm /KEw = (Mm/Mw ) (vm /vw)2

KEm /KEw = (1.63) (1/1.63)2 = 0.61

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