A 2.00-cm-tall object is located 18.0 cm in front of a converging lens with a focal length of 30.0 cm. (a) Use the lens equation and (b) a ray diagram to describe the type, location, and height of the image that is formed.
When object is placed between optic centre and focus of convex lens it forms a virtual enlarged image on the same side of object
Get Answers For Free
Most questions answered within 1 hours.