Question

A parallel plate capacitor with separation, d, is charged up to a surface charge density σ0....

A parallel plate capacitor with separation, d, is charged up to a surface charge density σ0. a) The plates are now disconnected from the charging device. The separation between the plates is now increased from d to D (D > d). How much work per unit area is done by the agent causing the increase in separation? b) When the plates are at a separation, d, and charge density σ0, they are attached to a battery that maintains the voltage fixed at the value corresponding to (d, σ0). Once again the surfaces are separated from d to D, but this time with the voltage fixed. How much work per unit area is performed by the agent causing the increase in separation? Discuss this result in the context of (a) above.

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