The power output of the Sun is 4.062×1026 W. If 81.5% of this is supplied by the proton-proton cycle, how many protons are consumed per second? Give your answer in 1038 protons per second.
Number of protons consumed per second will be given by:
Number of protons consumed per second = efficiency*total power*protons used in cycle/energy released
Using given values:
Total power = 4.062*10^26 W
energy released in single proton-proton cycle = 26.7 MeV = 26.7*10^6*1.6*10^-19
protons used in proton-proton cycle = 4
efficiency = 81.5% = 0.815
So,
Protons consumed per second = 0.815*4.062*10^26*4/(26.7*10^6*1.6*10^-19)
= 3.099*10^38
= 3.1*10^38 protons per second
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Extra Information:
energy released in single proton-proton cycle = 26.7 MeV (this values is taken from reference book college physics textbook)
proton-proton cycle is
2e + 41H ----> 4He + 2ve +
Energy released = dm*c^2 = (4*mass of proton - mass of helium)*c^2
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