Question

A student undergoes a first displacement of 6.0 m at an angle of 50 degrees north of east. The student undergoes a second displacement of 3.0 m at an angle of 40 degrees south of east. The magnitude of the total displacement is

6.71 m

2.67 m

3.86 m

2.30 m

6.16 m

Answer 1

From the above figure displacement d1is given by:

Now, Displacement d2 is given by:

So net displacement is given by :