Question

A 6.76 kg bowling ball is moving down a frictionless and bumpy hill. Its initial speed is 1.48 m/s.

1) What is the magnitude of its initial momentum? (in units of kg m/s). True or false

2) As the above ball frictionlessly moves down the hill, its potential energy and kinetic energy increase.

3) Its initial kinetic energy is:

A) 6.76 J,

B) 7.40 J,

C) 20.0 J,

D) 66.2 J, or

E) none of these

4) The initial elevation above the bottom of the hill is 15.1 m. (h = 0.00 m at the bottom) Thus, the initial potential energy is:

A) 1.02 x 10² J, B) 1.48 x 10² J, C) 1.00 x 10³ J, or   D) none of these

5) What is the total mechanical energy, E^tot, of the ball? (in units of Joules)

A) impossible to calculate, B) 168, C) 214, D) 1.01 x 10³, or E) none of these

6) As the ball moves down the hill, E^tot is constant and ΔPE = - ΔKE. True or false

7) When reaching the bottom of the hill, the ball's potential energy is zero. (recall that h = 0.00 at the bottom of the hill). True or false

8) At the hill's bottom, the value of the kinetic energy, KE, is (in units of Joules)

A) zero, B) 168, C) 214, D) 1.01 x 10², E) 1.01 x 10³, F) greater than 2,000, or G) none of these

9) At the bottom of the hill, the value of the speed, v, is (in m/s):

A) 6.76, B) 8.63, C) 12.2, D) 17.3, E) none of these

Answer 1