Question

7) A charge of -9 micro-coulombs with a mass of 11 kg is placed on a horizontal surface. A uniform electric field is applied either in the +y or -y direction (perpendicular to the surface). In order to lift the charge off the surface (i.e. the normal force becomes zero) what does the minimum magnitude of the field need to be and in what direction does it need to be applied? Answer in 106 N/C as in previous problems and if the field is in the -y direction, enter a negative sign.

8) A charge of +2 micro-coulombs is placed in a uniform electric field and electric force acting on the charge is 14.7 Newtons in the +x direction. What is the magnitude of the electric field in x 106 N/C and in what direction is it? Indicate the -x direction, by including a negative sign.

Answer 1