Question

Coulomb's law for the magnitude of the force F FF between two particles with charges Q QQ and Q ′ Q′Q^\prime separated by a distance d dd is |F|=K |Q Q ′ | d 2 |F|=K|QQ′|d2 , where K= 1 4π ϵ 0 K=14πϵ0 , and ϵ 0 =8.854× 10 −12 C 2 /(N⋅ m 2 ) ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q 1 q1q_1 = -20.0 nC nC , is located at x 1 x1x_1 = -1.675 m m ; the second charge, q 2 q2q_2 = 33.5 nC nC , is at the origin ( x x = 0). Part A What is ( F net3 ) x (Fnet3)x , the x-component of the net force exerted by these two charges on a third charge q 3 q3q_3 = 45.5 nC nC placed between q 1 q1 and q 2 q2 at x 3 x3x_3 = -1.145 m m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Answer 1