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An electric field of 16 V/m is produced through a cylindrical wire that has uniform radius of 1.8 mm. If the resistivity of the material is ρ= 6.8x10-6 Ω.m, calculate the current passing through the wire.
Select one:
a. 18 A
b. 32 A
c. 24 A
d. 12 A
Area of the wire, A =
* R2
Where R is the radius of the wire.
A =
* (1.8 * 10-3)2
= 10.18 * 10-6 m2
Consider the length of the wire as L
The resistance of the wire, R = (
* L) / A
Where
is the resistivity of the wire,
R = [(6.8 * 10-6) * L] / (10.18 * 10-6)
= 0.668 * L
-----------------------------------------------
The voltage drop in the wire, V = E * L
Where E is the electric field
V = 16 * L
-----------------------------------------
Current, I = V / R
= (16 * L) / (0.668 * L)
= 24 A (option c)
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