Question

A green chameleon is climbing up a wall and when it reaches the roof, a bug lands on its back. If the chameleon were to flick the big off of its back and fall to the ground, how far would the fly away from the wall before it hits the ground? The chameleon is 1.36 kg, the bug is 0.02 kg, and the roof is 3.65 meters above the ground. As the chameleon creates a flicking motion with its fingers at 4 m/s, the bug is flicked from a 35 degree angle.

Answer 1

The situation is summed up in the image below.

The distance x is to be found out.

The distance is given by the equation

Where v₀ is the velocity of the bug = 4 m/s

Now, the height of the projectile at any time t is given by

Where u = v₀ sin(35)

and g = 9.8 m/s^2

Thus,

When the fly hots the ground, h = -3.65 m (the roof is taken as zero.)

Thus,

Solving, we get

t = 1.128 s

Thus,