Question

a) An electron has a velocity of 7.0 x 106 m/s in the positive x direction...

a) An electron has a velocity of 7.0 x 106 m/s in the positive x direction at a point where the magnetic field has the components Bx = 3.0 T, By = 2.5 T, and Bz = 2.0 T. What is the magnitude of the acceleration of the electron at this point (in 1018 m/s2)? (me = 9.11 x 10-31 kg, e = 1.6 x 10-19 C)

b) A particle (q = 5.0 nC, m = 3.0 μg) moves in a region where the magnetic field has components Bx = 1.0 mT, By = 1.5 mT, and Bz = -4.0 mT. At an instant when the speed of the particle is 6.5 km/s and the direction of its velocity is 120° relative to the magnetic field, what is the magnitude of the acceleration of the particle (in m/s2)?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Thanks in advance, I couldn't find the answers to the following questions: Q1) A particle (q...
Thanks in advance, I couldn't find the answers to the following questions: Q1) A particle (q = –4.0 µC, m = 5.0 mg) moves in a uniform magnetic field with a velocity having a magnitude of 2.0 km/s and a direction that is 50° away from that of the magnetic field. The particle is observed to have a magnetic force with a magnitude of 29 ?N. What is the magnitude of the magnetic field? Q2) An electron has a velocity...
An electron in a TV camera tube is moving at 5.80×106 m/s in a magnetic field...
An electron in a TV camera tube is moving at 5.80×106 m/s in a magnetic field of strength 93 mT. Without knowing the direction of the field, what can you say about the greatest and least magnitude of the force acting on the electron due to the field? Maximum force? (in N) Minimum force? (in N) At one point the acceleration of the electron is 8.365×1016 m/s2. What is the angle between the electron velocity and the magnetic field? (deg)...
An electron moves at 2.50 x 106 m/s through a region in which there is a...
An electron moves at 2.50 x 106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.40 x 10-2 T. (a) What is the smallest possible magnitude of the acceleration of the electron due to the magnetic field?(1.5 marks) (b) What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? (c) If the actual acceleration of the electron is one-fourth of the largest magnitude in part...
An electron that has a velocity with x component 1.9 × 106 m/s and y component...
An electron that has a velocity with x component 1.9 × 106 m/s and y component 3.4 × 106 m/s moves through a uniform magnetic field with x component 0.033 T and y component -0.15 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity.
An electron that has a velocity with x component 2.0 × 106 m/s and y component...
An electron that has a velocity with x component 2.0 × 106 m/s and y component 3.9 × 106 m/s moves through a uniform magnetic field with x component 0.035 T and y component -0.21 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity.
TV Camera An electron in a TV camera tube is moving at 7.09 ? 106 m/s...
TV Camera An electron in a TV camera tube is moving at 7.09 ? 106 m/s in a magnetic field of strength 93.0 mT. (a) Without knowing the direction of the field, what can you say about the greatest and least magnitudes of the force acting on the electron due to the field? maximum force = N minimum force = N (b) At one point the acceleration of the electron is 4.9 ? 1014 m/s2. What is the angle between...
An electron has an initial velocity of 2.2×106 m/s in the +x direction. It enters a...
An electron has an initial velocity of 2.2×106 m/s in the +x direction. It enters a uniform electric field E = 382 N/C which is in the +y direction. What is the ratio of the y-component of the velocity of the electron to the x-component of the velocity after traveling 9 cm in the +x direction in the field? (Your result must include 2 digit after the decimal point and maximum of 5% of error is accepted in your answer....
An electron has an initial velocity of 2×106 m/s in the +x direction. It enters a...
An electron has an initial velocity of 2×106 m/s in the +x direction. It enters a uniform electric field E = 388 N/C which is in the +y direction. By how much, and in what direction, is the electron deflected after traveling 11 cm in the +x direction in the field? (Express the direction of deflexion by using positive and negative signs. Your result must be in cm's and include 1 digit after the decimal point. Maximum of 5% of...
A particle (q = 3.0 mC, m = 20 g) has a speed of 20 m/s...
A particle (q = 3.0 mC, m = 20 g) has a speed of 20 m/s when it enters a region where the electric field has a constant magnitude of 80 N/C and a direction which is the same as the velocity of the particle. What is the speed of the particle 3.0 s after it enters this region? A charge of 80 nC is uniformly distributed along the x axis from x = 0 to x = 0 m....
A particle travels with a velocity ?=6.00×10-5?―2.00×10-5? [m / s] and enters to a region where...
A particle travels with a velocity ?=6.00×10-5?―2.00×10-5? [m / s] and enters to a region where there is a magnetic field ?=0.500? ― 2.00? ― 1.40 ? [T]. Determine: a) magnitude and direction of the magnetic force experienced by the particle if it has a charge q = - 0.600 [nC] b) the smallest angle between the velocity and magnetic field vectors.