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A 2.92 kg particle has the xy coordinates (-1.90 m, 0.101 m), and a 4.04 kg...

A 2.92 kg particle has the xy coordinates (-1.90 m, 0.101 m), and a 4.04 kg particle has the xy coordinates (0.410 m, -0.405 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 3.96 kg particle such that the center of mass of the three-particle system has the coordinates (-0.876 m, -0.309 m)?

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Answer #1

We know the procedure for calculation of centre of mass of any no of given masses at any location. So we can apply that here on a three mass system in x-y plane.

We suppose the third mass to be placed at (x,y) and then by equating the given COM coordinates we can find the values of (x,y).

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