What is the maximum value of the electric field in an electromagnetic wave whose average intensity is 3.05 W/m2 ?
Answer is in V/m
For a continuous sinusoidal electromagnetic wave, the average intensity Iavg is given by, , where, c is the speed of light, μo is the permeability of free space, and Eo is the maximum electric field strength.
Given, Iavg = 3.05 W/m2
Known, c = 3 x 108
μo = 4 x 10-7
Thus, the maximum value of the electric field in the given electromagnetic wave is 47.955 V/m
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