Question

a soccer player is ready to deliver a kick to a ball. he will kick the ball with a force of 1350 N directed at an angle of 48 degree above horizontal. his foot will be in contact with the ball for 5.9x10^-3 s. what is the impulse delivered by the player's foot?

A volleyball player is ready to return the approaching ball with a speed of 11.0m/s. if she returns the ball in the same direction with a speed of 22.0 m/s what impulse did she need to deliver? the mass of a volleyball is 270g. answer in kg*m/s

Thanks

Answer 1

Impulse is the product of applied force and the time duraction for which it is applied.

I=Ft.

Also impulse is the change in momentum.

a) provided in question force F=1350N, time duration t=5.9*10^(-3)

Impulse=1350*5.9*10(-3)=7.965Ns

b)provided in question mass of volleyball

m=270g,

Initial speed vi=11m/s

Initial mimentum= 0.270*11=2.97kgm/s

Final speed vf=-22m/s (direction changed)

Final momentum=0.270*(-22)=5.94kgm/s

So magnitude of change in momentum=2.97kgm/s

So she need to deliver impulse of 2.97Ns of impulse