Question

1. An electron enters a magnetic field of magnitude 1.75T
directed vertically upward. If the electron’s initial velocity was
4.7x10^6 m/s, what is

a) the magnitude and direction of the magnetic force on the
electron.

b) the radius of its circular path.

Answer #1

In a 1.35 T magnetic field directed vertically upward, a
particle having a charge of magnitude 8.60 ?C and initially moving
northward at 4.68 km/s is deflected toward the east.
a)What is the sign of the charge of this particle? The charge is
negative or positive?
b)Find the magnetic force on the particle.

An electron moving in the +x direction enters a magnetic field
that is directed toward the -z direction (into the plane of the
page). The direction of the force on the electron is ?

An electron moves in a circular path perpendicular to a magnetic
field of magnitude 0.265 T. If the kinetic energy of the electron
is 4.50 ✕ 10−19 J, find the speed of the electron and
the radius of the circular path.
(a) the speed of the electron
m/s
(b) the radius of the circular path
μm

A large uniform magnetic field is depicted above directed into
the page with a magnitude of 0.20T. A proton is shot into the field
with a speed of 5.0x106 m/s and is trapped in a circular orbit.
a. (5) Determine the magnitude of the force on the
proton due to this magnetic field.
b. (10) Determine the radius of the proton’s path.
c. (5) Calculate the period of the proton’s
orbit.
d. (5) How much work is done by the...

An electron enters a magnetic field with speed v=1.41x10^6 m/s
and emerges after moving in a semicircular path with a diameter
10cm. Find the magnitude and the direction of the magnetic field,
and the time it took the electron to move on this path.

An electron enters a region of space containing a uniform
0.0000149-T magnetic field. Its speed is 121 m/s and it enters
perpendicularly to the field. Under these conditions, the electron
undergoes circular motion. Find the radius r of the electron\'s
path, and the frequency f of the motion.

An electron traveling at 106m/s horizontally enters a region
with a uniform electric field 10-6N/C directed upward. What will be
the acceleration of the electron (magnitude and direction)?
Calculate its vertical component of velocity 1s after it enters the
region with an electric field. What distance the electron will
travel in horizontal and vertical directions during first 1 second
after entering the region with an electric field?

An electron enters a magnetic field of 0.14 T with a velocity
perpendicular to the direction of the field. What is the value f
×10-10, where f is the frequency (in Hz) at which the electron
traverse a circular path?

1. An electron is moving through a magnetic field whose
magnitude is 8.99 × 10-4 T. The electron experiences only a
magnetic force and has an acceleration of magnitude 3.22 × 1014
m/s2. At a certain instant, it has a speed of 8.44 × 106 m/s.
Determine the angle (less than 90o) between the electron's velocity
and the magnetic field.
2.Suppose that an ion source in a mass spectrometer produces
doubly ionized gold ions (Au2+), each with a
mass of...

An
electron (mass 9.11x kg) travels at 2x10^5 m/s to the left. A
magnetic field of magnitude 1.2 T points out of the page.
a) What is the force (magnitude and direction) on the
electron?
b) What is the acceleration of the electron?
c) If the magnetic field is uniform in this region, the
electron will follow a circular path. What is the radius of the
circle?
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