Question

At time t = 0, a 4.0 kg particle with velocity v with arrow = (5.0...

At time t = 0, a 4.0 kg particle with velocity v with arrow = (5.0 m/s) i hat − (6.0 m/s) j is at x = 4.0 m, y = 2.0 m. It is pulled by a 6.0 N force in the negative x direction. (a) What is the angular momentum of the particle about the origin? (Express your answer in vector form.) (b) What torque about the origin acts on the particle? (Express your answer in vector form.) N · m (c) At what rate is the angular momentum of the particle changing?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 3.65 kg particle with velocity v→=(8.97m/s)î-(4.43m/s)ĵ is at x = 7.38 m, y = 5.02...
A 3.65 kg particle with velocity v→=(8.97m/s)î-(4.43m/s)ĵ is at x = 7.38 m, y = 5.02 m. It is pulled by a 2.09 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?
The velocity of a particle (m = 10 mg, q = –4.0 μC) at t =...
The velocity of a particle (m = 10 mg, q = –4.0 μC) at t = 0 is 30 m/s in the positive x direction. If the particle moves in a uniform electric field of 20 N/C in the positive x direction, what is the particle's speed (in m/s) at t = 5.0 s?
A particle is located at the vector position r with arrow = (9.00î + 12.00ĵ) m...
A particle is located at the vector position r with arrow = (9.00î + 12.00ĵ) m and a force exerted on it is given by F with arrow = (7.00î + 6.00ĵ) N. (a) What is the torque acting on the particle about the origin? τ = N · m (b) Can there be another point about which the torque caused by this force on this particle will be in the opposite direction and half as large in magnitude? Yes...
- The velocity of a particle (m = 10 mg, q = -4.0 mC) at t...
- The velocity of a particle (m = 10 mg, q = -4.0 mC) at t = 0 is 20 m/s in the positive x direction. If the particle moves in a uniform electric field of 20 N/C in the positive x direction, what is the particle's speed at t = 5.0 s? What is the distance the particle moves in the field?
At time t = 4 sec, a particle of mass M = 4.5 kg is at...
At time t = 4 sec, a particle of mass M = 4.5 kg is at the position (x,y,z) = (4,4,6) m and has velocity (2,1,-2) m/s. 1)What is the x component of the particle's angular momentum about the origin? 2)What is the y component of the particle's angular momentum about the origin? 3)What is the z component of the particle's angular momentum about the origin? 4)Now an identical particle is placed at (x,y,z) = (-4,-4,-6) m, with velocity (-2,-1,2)...
At time t = 11.5 sec, a particle of mass M = 5 kg is at...
At time t = 11.5 sec, a particle of mass M = 5 kg is at the position (x,y,z) = (4,4,6) m and has velocity (2,1,-2) m/s. 1) What is the x component of the particle's angular momentum about the origin? 2) What is the y component of the particle's angular momentum about the origin? 3) What is the z component of the particle's angular momentum about the origin? 4) Now an identical particle is placed at (x,y,z) = (-4,-4,-6)...
A 14.00 kg particle starts from the origin at time zero. Its velocity as a function...
A 14.00 kg particle starts from the origin at time zero. Its velocity as a function of time is given by v with arrow = 9t2î + 4tĵ where v with arrow is in meters per second and t is in seconds. (Use the following as necessary: t.) (a) Find its position as a function of time. r =________ (c) Find its acceleration as a function of time. a=_______m/s^2 ( (d) Find the net force exerted on the particle as...
A particle is at the position (x,y,z)=(1.0,2.0,3.5)m. It is traveling with a vector velocity (−5.2,2.6,−3.0)m/s. Its...
A particle is at the position (x,y,z)=(1.0,2.0,3.5)m. It is traveling with a vector velocity (−5.2,2.6,−3.0)m/s. Its mass is 3.8 kg . (PART A)What is its vector angular momentum about the origin? Find the x-component. (Express your answer using two significant figures.) (PART B) Find the y-component. Express your answer using two significant figures. (PART C) Find the z -component. Express your answer using two significant figures.
A particle (q = -4.0 μC, m = 5.0 mg) moves in a uniform magnetic field....
A particle (q = -4.0 μC, m = 5.0 mg) moves in a uniform magnetic field. If the magnetic field strength is B, the speed of the particle is v, and the angle that the particle’s velocity makes with the magnetic field direction is q, in which of the following cases would the magnitude of the particle’s acceleration be the largest? A. v = 2.0 km/s, B = 9.1 mT, q = 90° B. v = 2.0 km/s, B =...
A 11.00 kg particle starts from the origin at time zero. Its velocity as a function...
A 11.00 kg particle starts from the origin at time zero. Its velocity as a function of time is given by v with arrow = 9t2î + 3tĵ where v with arrow is in meters per second and t is in seconds. (Use the following as necessary: t.) (a) Find its position as a function of time. (b) Describe its motion qualitatively. (c) Find its acceleration as a function of time. (d) Find the net force exerted on the particle...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT