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Suppose the Earth's magnetic field at the equator has magnitude 0.000047 T and a northerly direction...

Suppose the Earth's magnetic field at the equator has magnitude 0.000047 T and a northerly direction at all points. How fast must a singly ionized uranium atom (m=238u, q=e) move so as to circle the Earth 1.48 km above the equator? Give your answer in meters/second.

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