Question

Outside the space shuttle, you and a friend pull on two ropes to dock a satellite whose mass is 800 kg. The satellite is initially at position <3.7, -1.1, 2.7> m and has a speed of 6 m/s. You exert a force <-500, 400, 300> N. When the satellite reaches the position <2.6, 2.5, 16.5> m, its speed is 8.35 m/s. How much work did your friend do?

Answer 1

given :

m = mass = 8800 kg

initial position =

final position =

initial speed = v1 = 6 m/s

final speed = v2 = 8.35 m/s

force exerted by me =

Work done by my force =

  

Applying work energy principle :

work done by my force + workdone by my friend's force = change in kinetic energy

=> workdone by my friend's force = change in kinetic energy - work done by my force

  

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