Question

A proton collides elastically with another proton that is initially at rest. The incoming proton has an initial speed of 4.00e5 m/s. The incoming proton has an initial speed of 4.00e5 m/s and makes a glancing collision with the second proton (at close separations, the protons exert a repulsive electrostatic force on each other). After the collision, one proton moves off at an angle of 30.0 degrees to the original direction of motion and the second deflects at an angle of __ to the same axis. Find the final speeds of the two protons and the angle ___.

v1f = ___

a. 3.46e5

b. 4.46e5

c. 5.46e5

d. 2.46e5

v2f =

a. 5.00e5

b. 4.00e5

c. 3.00e5

d. 2.00e5

angle ____ =

a. 30.0

b. 60.0

c. 90.0

d. 45.0

Please answer clearly and explain your steps N E A T L Y!! Thanks!!!!

Answer 1

please rate the answer. It helps me a lot. Thank you ?