Question

An electron is held 18.0 m above the ground. How far apart would two different electrons need to be held in order to have the same potential energy as the first electron?

What is the potential 5.3 mm away from a 1.6 μC point charge? a. What distance from a 15 nC charge would have the same potential?

Answer 1

1) potential energy = mgh

= 9.1 × 10 ^-31 × 9.8 × 18

= 1.6 × 10 ^-28 = k q ² /r

r= 9 × 10 ⁹ ×(1.6× 10 ^-19)² /1.6 × 10 ^-28

r = 1.44 m (distance between two electrons so as to have same potential energy)

----------------

2) potential = kq/r

= 9× 10 ⁹ × 1.6 × 10 ^-9 /5.3 × 10 ^-3

= 2717 volts .

-----------

3)

2717 = 9 × 10 ⁹ × 15 × 10 ^-9 /r

r = 0.05 m

Please ask your doubts or queries in the comment section below.

Please kindly upvote if you are satisfied with the solution.

Thank you.